Say you are running a 2g/L product from a ten-day process at your 1 x 6000L plant, with strict orders from management to minimize downtime. This product is selling like gangbusters, which means every gram you make gets sold, which means you've got to make the most of the 80-day campaign allotted for this product.
The volumetric productivity for the process is 2g/L/10days = 0.2 g/L/day.Running a 6000L capacity plant gives you
- 12 kilos every 10 days.
- 8 run slots given the 80-day campaign
- Maximum product is going to be: 96 kg for the campaign.
But suppose your Manufacturing Sciences team ordered in-process titer measurements and found that Day 8 titers were 1.8 grams per liter. Harvesting at day 8 means:
- 10.8 kilos every eight days.
- 10 run slots given the 80-day campaign
- Maximum product is going to be 108 kg.
There are a lot of assumptions here:
- Your raw material costs are low relative to the price at which you can sell your product
- Your organization is agnostic to doing more work (ten runs instead of eight).