The Bertrand's Box Paradox refers to this puzzle:

You have 3 boxes before you.

Question:

Well, If I withdrew a gold coin from one a random selection of the 3 boxes, then I must have either Box A or Box B. Since I have 2 remaining choices: one favors a gold coin and the other favors a silver coin, then the chances of me pulling out a gold coin is 50% (aka 50/50).

Seems like it should be, right? Turns out it's

Here's how I wrangled this problem. I did it by using differing gold and silver coins.

From here, it's pretty easy to see that my second coin has 2 out of 3 chances of being gold and 1 out of 3 chances at being silver.

You have 3 boxes before you.

- Box A contains 2 gold coins.
- Box B contains 1 gold coin and 1 silver coin.
- Box C contains 2 silver coins.

Box A | |

Box B | |

Box C |

Question:

**Suppose you chose a box at random and withdrew one gold coin. What are the chances that the next coin is also gold?**Well, If I withdrew a gold coin from one a random selection of the 3 boxes, then I must have either Box A or Box B. Since I have 2 remaining choices: one favors a gold coin and the other favors a silver coin, then the chances of me pulling out a gold coin is 50% (aka 50/50).

Box A | |

Box B |

Seems like it should be, right? Turns out it's

**wrong.**Here's how I wrangled this problem. I did it by using differing gold and silver coins.

Box A | |

Box B | |

Box C |

So 3 boxes at 2 coins a piece means there are actually 6 possible outcomes in which I can randomly select a box and pull out coins. Here they are:

These are my only six options. Per the paradox, I withdrew a gold coin first and not a silver coin. This means that I didn't pick Box C's 2 possibilities. It also means that I didn't pick 1 of 2 Box B possibilities.

Essentially, I have 3 possibilities left:

1st coin | 2nd coin | ||
---|---|---|---|

1 | Choose Box A and snag the Gold Eagle first. | ||

2 | Choose Box A and snag the Gold Buffalo first | ||

3 | Choose Box B and snag the Gold Eagle first | ||

4 | Choose Box B and snag the Silver Eagle first | ||

5 | Choose Box C and select the Silver Eagle. | ||

6 | Choose Box C and grab a Silver coin. |

These are my only six options. Per the paradox, I withdrew a gold coin first and not a silver coin. This means that I didn't pick Box C's 2 possibilities. It also means that I didn't pick 1 of 2 Box B possibilities.

Essentially, I have 3 possibilities left:

1st coin | 2nd coin | ||
---|---|---|---|

1 | Box A: Gold Eagle first, then Gold Buffalo | ||

2 | Box A: Gold Buffalo, then Gold Eagle | ||

3 | Box B: Gold Eagle, then Silver Eagle |

From here, it's pretty easy to see that my second coin has 2 out of 3 chances of being gold and 1 out of 3 chances at being silver.

And thus correct answer to

Why does this talk of probabilities matter to a Manufacturing Sciences team or cell culture engineer?

Well, understanding the math behind bioreactor contamination... or recovery step yields... is one of the foundations in explaining real phenomena. This matters is because your biological system is multivariate.

Not only that, your process steps are sequential. Production cultures come after inoculum cultures. Harvests after production cultures. ProA after harvest... so on and so forth. The success of this step often depend on the outcome of the previous step. And CofA attributes measured at a late purification step could be caused by some factor at the production culture stage.

Large-scale biologics manufacturing is complex... far more complex than picking a box with 2 coins and pulling them out one at a time. Yet the math behind the Bertrand's Box Paradox shows us that we muggles are susceptible to missing the mark when conditional probabilities are involved.

Credits: Images are from the US Mint and therefore in the public domain.

**Bertrand's Box Paradox is 2/3 or 66.67%.**Why does this talk of probabilities matter to a Manufacturing Sciences team or cell culture engineer?

Well, understanding the math behind bioreactor contamination... or recovery step yields... is one of the foundations in explaining real phenomena. This matters is because your biological system is multivariate.

Not only that, your process steps are sequential. Production cultures come after inoculum cultures. Harvests after production cultures. ProA after harvest... so on and so forth. The success of this step often depend on the outcome of the previous step. And CofA attributes measured at a late purification step could be caused by some factor at the production culture stage.

Large-scale biologics manufacturing is complex... far more complex than picking a box with 2 coins and pulling them out one at a time. Yet the math behind the Bertrand's Box Paradox shows us that we muggles are susceptible to missing the mark when conditional probabilities are involved.

Credits: Images are from the US Mint and therefore in the public domain.

## 2 comments:

I have two children, including at least one boy. What are the chances I have two boys? Think about it for a moment, while I give you some history.

Joseph Bertrand published his "Box Paradox" in 1889 as a cautionary tale, about the dangers of treating probability problems based on "the information" alone. What you need to know is how you got the information. But you didn’t discuss his actual paradox.

If you accept the intuitive answer of 50% for your problem (yes, I know it is wrong), then you would also have to say there was a 50% chance the remaining coin is silver if the coin you withdraw is silver.

But then, if you withdraw a coin and hold it in your hand without looking at it, you would have to say there is a 50% chance that the coin in your hand is the same kind of coin as the coin in the box.

But that means that the chances a random box has two of the same kind of coin are 50%. We know this probability must be 67%. This is the paradox. The solution you gave above is the resolution of the paradox, since it shows that 50% is not correct.

And while that solution is correct for the problem as you stated it, it isn't always enough. Suppose that after you pick the box, I look inside of it and tell you that there is a gold coin instead of you withdrawing a coin. 50% is still wrong, but you can't use the "There are six cases, not three" argument, because there are only four cases. The correct solution is that, if I tell you about only one kind of coin, there is a 100% chance I will tell you about gold if you chose the box with two gold coins, but only a 50% chance if the box had a gold and a silver. That makes the answer (100%)/(100%+50%)=67%.

Most puzzle books that "solve" the Two Child Problem I gave at the start of this comment will say the answer is 33%. There are three possible family types that include a boy, and only one has two. But that's wrong; in fact, the problem is identical to Bertrand's Box Problem if you add a fourth box, and put a gold coin and a silver coin in it. It seems that most of these authors failed to heed Bertrand's cautionary tale, which is quite sad, because many of them also present his [problem in the same books.

OMG i was going nuts trying to wrap my head around the whole 2/3 chance remaining after selecting the first coin.....but using seperate coins made this soooooooooooo much easier....makes perfect sense now....cheers

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